"""
编写一个函数，其作用是将输入的字符串反转过来。输入字符串以字符数组 char[] 的形式给出。

不要给另外的数组分配额外的空间，你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。

你可以假设数组中的所有字符都是 ASCII 码表中的可打印字符。

 

示例 1：

输入：["h","e","l","l","o"]
输出：["o","l","l","e","h"]
示例 2：

输入：["H","a","n","n","a","h"]
输出：["h","a","n","n","a","H"]

作者：力扣 (LeetCode)
链接：https://leetcode-cn.com/leetbook/read/tencent/xxj50s/
来源：力扣（LeetCode）
著作权归作者所有。商业转载请联系作者获得授权，非商业转载请注明出处。
"""
from typing import List


class Solution:
    def reverseString(self, s: List[str]) -> None:
        """
        Do not return anything, modify s in-place instead.
        """
        mid = len(s) // 2
        for i in range(mid):
            s[i], s[-(i + 1)] = s[-(i+1)], s[i]


if __name__ == '__main__':
    arr = ["h","e","l","l","o"]
    sol = Solution()
    sol.reverseString(arr)
    print(arr)
